X^2-12x+10=20

Solution for X^2-12x+10=20 equation:

X^2-12X+10=20

We move all terms to the left:

X^2-12X+10-(20)=0

We add all the numbers together, and all the variables

X^2-12X-10=0

a = 1; b = -12; c = -10;
Δ = b2-4ac
Δ = -122-4·1·(-10)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{46}}{2*1}=\frac{12-2\sqrt{46}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{46}}{2*1}=\frac{12+2\sqrt{46}}{2}
$